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your_next_idea.pyPY

# Find 24. One step at a time.
def find_your_next_step():
    numbers = [3, 7, 12, 18, 24, 31, 42]
    target = 24
    return binary_search(numbers, target)

BINARY SEARCH / PREVIEWtarget 24

122

183

244

315

426

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Different problems.
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Explore algorithms

pattern_library.pyPython

Binary searchO(log n)

01def binary_search(nums, target):02    left, right = 0, len(nums) - 103    while left <= right:04        mid = (left + right) // 205        if nums[mid] == target:06            return mid07        if nums[mid] < target:08            left = mid + 109        else:10            right = mid - 111    return -1

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